24x^2+26x-35=0

Solution for 24x^2+26x-35=0 equation:

24x^2+26x-35=0

a = 24; b = 26; c = -35;
Δ = b2-4ac
Δ = 262-4·24·(-35)
Δ = 4036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4036}=\sqrt{4*1009}=\sqrt{4}*\sqrt{1009}=2\sqrt{1009}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{1009}}{2*24}=\frac{-26-2\sqrt{1009}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{1009}}{2*24}=\frac{-26+2\sqrt{1009}}{48}
$